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INTEGRAIS DE GRACELI [28]

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February 11, 2025

ψ = ψ / $E=mc^{2}$

ψ = ψ / $E=mc^{2}$ / $E=hf$

ψ = ψ / $E=mc^{2}$ / $\lambda ={\frac {h}{p}}$

ψ = ψ / $E=mc^{2}$ / $G_{\mu \nu }=R_{\mu \nu }-{\frac {1}{2}}Rg_{\mu \nu }$

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